$\dfrac{{\cal B}(B_s^0 \to \phi(1020) \phi(1020))}{{\cal B}(B_s^0 \to J/\psi \phi(1020))}$

ExperimentMeasurement [10-2]$\Delta\chi^2$ReferenceComments
Average$1.78 \pm0.24$The PDG average is a result of a fit including input from other measurements.
CDF$1.78 \pm0.14 \pm0.20$0.00 Phys.Rev.Lett. 107,261802 (2011)