$\frac{ {\cal{B}}(B^0_s \to \bar{K}^(892)^0 \mu^+\mu^-)}{ {\cal{B}}(B^0_s \to J/\psi \bar{K}^(892)^0 ) \times {\cal{B}}(J/\psi \to \mu^+ \mu^-)}$

Experiment	Measurement [10^-2]	$\Delta\chi^2$	Reference	Comments
Average	$1.40 \pm0.42$
LHCb	$1.4 \pm0.4 \pm0.1$	0.00	JHEP 07,020 (2018)	Multiple systematic uncertainties are added in quadrature.

$\frac{ {\cal{B}}(B^0_s \to \bar{K}^*(892)^0 \mu^+\mu^-)}{ {\cal{B}}(B^0_s \to J/\psi \bar{K}^*(892)^0 ) \times {\cal{B}}(J/\psi \to \mu^+ \mu^-)}$